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100% Pass 2025 ISTQB ISTQB-CTAL-TA: (ISTQB CTAL-TA) ISTQB Certified Tester Advanced Level - Test Analyst (Syllabus 2012) Latest Exam Guide

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ISTQB Certified Tester Advanced Level - Test Analyst (Syllabus 2012) certification exam is an excellent opportunity for software testers to advance their careers and demonstrate their expertise in test analysis. This globally recognized certification is based on a comprehensive syllabus and covers a range of topics related to software testing. By obtaining this certification, professionals can improve their job prospects, enhance their skills, and work in any industry that requires software testing expertise.

ISTQB (ISTQB CTAL-TA) ISTQB Certified Tester Advanced Level - Test Analyst (Syllabus 2012) Sample Questions (Q70-Q75):

NEW QUESTION # 70
Which of the following descriptions is an example of the use of defect taxonomies?

A. Grouping defects found during execution by functional area
B. Running tests with the aim of finding as many defects as possible
C. Using a list of known defect types to penetrate the security of computer systems
D. Following a defect management process throughout testing

Answer: C

Explanation:
The description that is an example of the use of defect taxonomies is using a list of known defect types to penetrate the security of computer systems. A defect taxonomy is a classification of defects based on their characteristics, causes, or effects. A defect taxonomy can be used to design test cases that target specific types of defects or vulnerabilities in a system or component. Verified References: [ISTQB Certified Tester Advanced Level Test Analyst CTAL-TA], Section 3.8.1, page 47.

NEW QUESTION # 71
A web-based system is being developed to support the administration of tennis tournaments.
The system provides advice on how much money to offer each player as their individual attendance fee. The amount depends on acombinationof the following factors:
* Overall attendance fund (divided into five numeric ranges)
* Player's current world ranking (divided into ten numeric ranges)
* Whether it is a local tournament for the player (YES or NO)
* Their relationship with the tournament sponsors (clothing, equipment, or endorsement)
* Their previous attendance history at this event (finalist, played, withdrew before event, or withdrew during event) The new system needs to be ready for the next tournament in just a few months' time, so testing schedules will be severely challenged.
Which specification-based technique would be the BEST choice in the circumstances?
SELECT ONE OPTION:

A. Pairwise testing
B. State Transition testing
C. Use case testing
D. Equivalence partitioning

Answer: A

Explanation:
Comprehensive and Detailed In-Depth Explanation:
* A (Use case testing):Not suitable as it focuses on user interactions rather than combinations of input values.
* B (State Transition testing):Irrelevant since the focus is not on state changes.
* C (Equivalence partitioning):Good for partitioning input values but not efficient for combinations.
* D (Pairwise testing):Correct. This technique is highly efficient for coveringcombinations of multiple variableswith fewer test cases, which is crucial when the schedule is tight.
Therefore, the correct answer isD (Pairwise testing).

NEW QUESTION # 72
What is main difference between user experience and usability?

A. Usability is evaluated via reviews; the user experience is evaluated via surveys
B. Usability relates to people's perceptions and responses; user experience relates to characteristics of the software product.
C. There is no difference between user experience and usability, they are the same.
D. User experience relates to people's perceptions and responses; usability relates to characteristics of the software product.

Answer: D

Explanation:
The main difference between user experience and usability is that user experience relates to people's perceptions and responses when using or anticipating using a system or component, while usability relates to characteristics of the software product that enable it to be used effectively, efficiently, and satisfactorily under specified conditions. Verified References: [ISTQB Certified Tester Advanced Level Test Analyst CTAL- TA], Section 5.2.1, page 63.

NEW QUESTION # 73
A tablet manufacturer offers the following options for its customers:
* Colour:Black, White, Silver, Gold
* Model:Standard, Mini, Pro
* Gigabytes:32, 64, 128, 256
* Connectivity:Wifi-only, Wifi+Cellular
When applying the pairwise test technique, how many TEST CASES would be needed to ensure that ALL pair combinations are tested?
SELECT ONE OPTION

A. 0
B. 1
C. 2
D. 3

Answer: A

Explanation:
Comprehensive and Detailed in Depth Explanation:
Pairwise testing is a combinatorial test design technique in which test cases are designed to execute all possible discrete combinations of each pair of input parameters. This technique significantly reduces the number of test cases compared to exhaustive testing while still covering pairwise interactions.
To calculate the number of test cases:
* Colour: 4 options
* Model: 3 options
* Gigabytes: 4 options
* Connectivity: 2 options
Pairwise testing does not necessarily involve multiplying all options, as it aims to cover all pairs. Using an orthogonal array or pairwise tool, the minimum number of test cases that cover all pairs for these parameters is
16. Hence, the answer isC (16).

NEW QUESTION # 74
A software component for a game application calculates a player's trophy level based on two input parameter values: Points Earned and Level of Difficulty. A total score is calculated by the component as:
Total Score = Points Earned × Level of Difficulty
The trophy levels are:
* Blue- total score equal to or less than 40
* Silver- total score > 40
* Gold- total score > 70
* Diamond- total score > 80
* Platinum- total score > 90
The component then outputs the correct trophy level.
Applying theEquivalence Partition test design techniqueto this component, what percentage of output partitions have been exercised by the following suite of test cases?
* Player 1 - Points earned 25, level of difficulty 2
* Player 2 - Points earned 20, level of difficulty 3
* Player 3 - Points earned 30, level of difficulty 1
SELECT ONE OPTION:

A. 60%
B. 10%
C. 40%

Answer: C

Explanation:
Comprehensive and Detailed In-Depth Explanation:
To determine the answer, we first calculate the total score for each player:
* Player 1:25×2=5025 imes 2 = 5025×2=50 (Silver)
* Player 2:20×3=6020 imes 3 = 6020×3=60 (Silver)
* Player 3:30×1=3030 imes 1 = 3030×1=30 (Blue)
The output equivalence partitions based on the trophy levels are:
* Blue:Total score # 40
* Silver:Total score > 40 and # 70
* Gold:Total score > 70 and # 80
* Diamond:Total score > 80 and # 90
* Platinum:Total score > 90
From the given test cases, the following partitions have been exercised:
* Blue (Player 3)
* Silver (Player 1 and Player 2)
Out of the 5 possible output partitions (Blue, Silver, Gold, Diamond, Platinum), only2 partitions (Blue and Silver)have been exercised. Therefore, the percentage of partitions covered is:
A number and a percentage sign AI-generated content may be incorrect.
Hence, the correct answer isB (40%).

NEW QUESTION # 75
......

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